WebAn element is called a peak element if its value is not smaller than the value of its adjacent elements (if they exists). Given an array arr [] of size N, Return the index of any one of its peak elements. Note: The generated output will always be 1 if the index that you return is correct. Otherwise output will be 0. Input: N = 3 arr [] = {1,2,3 ... WebMar 15, 2024 · Practice. Video. Given an array arr [] consisting of N ( > 2) integers, the task is to find the peak index of the array. If the array doesn’t contain any peak index, then print …
Find Peak Element - Coding Ninjas
WebJun 11, 2024 · 1 Nth Digit 2 Smallest Good Base... 782 more parts... 3 Minimum Cost of Buying Candies With Discount 4 Number of Ways to Divide a Long Corridor 5 Remove One Element to Make the Array Strictly Increasing 6 Swap Nodes in Pairs 7 Group the People Given the Group Size They Belong To 8 Number of Pairs of Strings With Concatenation … WebAug 1, 2024 · Problem paraphrased: Given an array that resembles a mountain in that the elements in the array from left to right will change from increasing in value to decreasing in value one time, return the… aeria bollene
Peak of Mountain Array - Binary Search / Implicitly Sorted Array
Webalevelalt / Peak-Index-in-a-Mountain-Array Public Star main 1 branch 0 tags Go to file Code alevelalt Initial commit 067ed5a 2 minutes ago 1 commit README.md Initial commit 2 minutes ago README.md Peak-Index-in-a-Mountain-Array About No description, website, or topics provided. Readme 0 stars 1 watching 0 forks No releases published Web22. Yes, you can do it in O (log n) using an idea similar to binary search. Point to the middle of the vector and check its neighbours. If it is greater than both of its neighbours, then return the element, it is a peak. If the right element is greater, then find the peak recursively in the right side of the array. WebIn other words, peak can’t be the first or last element in the mountain array. int climb = 0 while (climb < n - 1 && X[climb] < X[climb + 1]) climb = climb + 1 if (climb == 0 climb == n - 1) return false If peak is present at some middle element, we run another loop from that position to check strictly decreasing order or elements. aeria aimatos